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If the length of a simple pendulum is increased by 2%, then the time period

1. increases by 2%
2. decreases by 2%
3. increases by 1%
4. decreases by 1%

Correct answer: increases by 1%

Solution

The time period of a simple pendulum is proportional to the square root of its length (T ∝ √L). If the length increases by 2%, the time period increases by approximately √(1.02) ≈ 1.01, which corresponds to a 1% increase.

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