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A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:

1. T/8
2. T/12
3. T/2
4. T/4

Correct answer: T/8

Solution

In SHM, the motion is sinusoidal. The time taken to travel from the equilibrium position to half the amplitude corresponds to one-eighth of the total period, as the particle moves fastest near equilibrium. Thus, the answer is T/8.

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