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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be

1. T
2. T / √2
3. 2T
4. √2T

Correct answer: √2T

Solution

The period of oscillation for a spring-mass system is given by T = 2π√(m/k). When another mass M is added, the total mass becomes 2M, so the new period becomes T' = 2π√(2M/k) = √2T.

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