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A particle is executing a simple harmonic motion of amplitude 'a'. Its potential energy is maximum when the displacement from the position of the maximum kinetic energy is
- 0
- ±a
- ±a/2
- −a/2
Correct answer: ±a
Solution
In simple harmonic motion, the potential energy is maximum when the displacement is at its maximum amplitude, ±a, because all the energy is stored as potential energy at the extreme positions.
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