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The particle executing simple harmonic motion has a kinetic energy K₀ cos² ωt. The maximum values of the potential energy and the total energy are respectively
- K₀/2 and K₀
- K₀ and 2K₀
- K₀ and K₀
- 0 and 2K₀
Correct answer: K₀ and K₀
Solution
In simple harmonic motion, the total energy is constant and equals the maximum kinetic energy, which is K₀. The maximum potential energy is also equal to the total energy, which is K₀.
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