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A particle executing S.H.M. has amplitude 0.01m and frequency 60 Hz. The maximum acceleration of the particle is

1. 144 π² m/s²
2. 120 π² m/s²
3. 80 π² m/s²
4. 60 π² m/s²

Correct answer: 144 π² m/s²

Solution

The maximum acceleration in SHM is given by a_max = ω²A, where ω = 2πf. Here, f = 60 Hz and A = 0.01 m. Substituting, ω = 2π × 60 = 120π rad/s. Thus, a_max = (120π)² × 0.01 = 144π² m/s².

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