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We know that efficiency of Carnot Engine η = T1 − T2/T1.

1. Where, T1 is temp. of source and T2 is temp. of sink
2. 0.40 = T1 − 300/T1 ⇒ T1 = 300/0.40T1
3. Efficiency of engine B, η = 1 − T2/T1
4. Change in entropy is given by ΔS = dQ/T = ΔQ/T = mLf/T

Correct answer: Where, T1 is temp. of source and T2 is temp. of sink

Solution

Option A is correct because it correctly defines the terms T1 and T2 in the Carnot engine efficiency formula, where T1 is the temperature of the source and T2 is the temperature of the sink.

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