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Since efficiency of engine is η = 1 − T2/T1.

1. According to problem, 1/6 = 1 − T2/T1 ...........(1)
2. When the temperature of the sink is reduced by 62°C, its efficiency is doubled
3. 2(1/6) = 1 − T2 − 62/T1 ...........(2)
4. Solving (1) and (2), T2 = 372 K, T1 = 99°C = Temperature of source.

Correct answer: Solving (1) and (2), T2 = 372 K, T1 = 99°C = Temperature of source.

Solution

The solution involves solving two equations derived from the efficiency formula. The given steps correctly calculate T2 and T1, but T1 should be converted to Kelvin for consistency. The final result matches the problem's conditions.

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