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Efficiency of ideal heat engine, η = (1 − T2/T1).

1. Sink temperature, T2 = 100°C = 100 + 273 = 373 K
2. Source temperature, T1 = 0°C = 0 + 273 = 273 K
3. Percentage efficiency, η% = (1 − T2/T1) × 100
4. η% = (1 − 273/373) × 100 = 100 × 100/373 = 26.8%

Correct answer: η% = (1 − 273/373) × 100 = 100 × 100/373 = 26.8%

Solution

The efficiency formula is correctly applied, and the temperatures are converted to Kelvin. The calculation for η% is accurate, leading to the correct result of 26.8%.

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