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Work done = Area under curve ACDBA. BC is isobaric process.

1. BC is isobaric process, W = P × (V2 − V1) = 240 J
2. ΔQ = 600 + 200 = 800 J
3. Using ΔQ = ΔU + ΔW ⇒ ΔU = ΔQ − ΔW = 800 − 240 = 560 J
4. Since AB is an isochoric process i.e., ΔV = 0 so, no work is done.

Correct answer: BC is isobaric process, W = P × (V2 − V1) = 240 J

Solution

Option A is correct because BC is an isobaric process, and the work done in an isobaric process is given by W = P × ΔV, which matches the calculation provided.

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