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T1 P1^(1−γ) = T2 P2^(1−γ).

1. T2/T1 = (P1/P2)^(1−γ)
2. T2 = T1 × (P1/P2)^(1−γ)
3. T2 = 300 × (8/25)^(1−γ) = 142°C
4. Efficiency of ideal heat engine, η = (1 − T2/T1)

Correct answer: T2 = T1 × (P1/P2)^(1−γ)

Solution

The given equation represents the relation between temperature and pressure for an adiabatic process. Rearranging it, T2 = T1 × (P1/P2)^(1−γ) is the correct expression.

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