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Internal energy is the state function. In cyclic process, ΔU = 0.

1. According to 1st law of thermodynamics ΔQ = ΔU + W
2. So heat absorbed ΔQ = W = Area under the curve = -(2V) (P) = -2PV
3. So heat rejected = 2PV
4. None of the above

Correct answer: So heat rejected = 2PV

Solution

In a cyclic process, the change in internal energy (ΔU) is zero, so the heat absorbed (ΔQ) equals the work done (W). The heat rejected is given as 2PV, which matches option C.

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