Exams › NEET › Physics

A thermodynamic system is taken from state A to B along ACB and is brought back to A along BDA as shown in the PV diagram. The net work done during the complete cycle is given by the area

1. P₁ACBP₂P₁
2. ACBBA'A
3. ACBDA
4. ADBBA'A

Correct answer: ACBDA

Solution

The net work done in a thermodynamic cycle is equal to the area enclosed by the path of the cycle on the PV diagram. Here, the area enclosed by the path ACBDA represents the net work done.

Related NEET Physics questions

• If for a gas \( \frac{\boldsymbol{R}}{\boldsymbol{C}_{\boldsymbol{v}}}=\mathbf{0 . 6 7}, \) then the gas is made up of molecules which are :
• Use of thermometer is based on which law of thermodynamics?
• The total kinetic energy of 1 mole of \( N_{2} \) at \( 27 \mathrm{C} \) will be approximately
• The quantity \( \frac{2 U}{f k T} \) represents (where \( U= \) internal energy of gas
• A cyclic heat engine does \( 50 \mathrm{kJ} \) of work per cycle. If efficiency of engine is \( 75 \% \) the heat rejected per cycle will be:
• Thermistor material is pressed

⚔️ Practice NEET Physics free + battle 1v1 →