Exams › NEET › Physics

A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is:

1. P₀V₀
2. 2P₀V₀
3. 3P₀V₀
4. Zero

Correct answer: 2P₀V₀

Solution

The work done in a cyclic process is equal to the area enclosed by the cycle on the PV diagram. For the given process, the area is a rectangle with sides P₀ and 2V₀, so the work done is 2P₀V₀.

Related NEET Physics questions

• If for a gas \( \frac{\boldsymbol{R}}{\boldsymbol{C}_{\boldsymbol{v}}}=\mathbf{0 . 6 7}, \) then the gas is made up of molecules which are :
• Use of thermometer is based on which law of thermodynamics?
• The total kinetic energy of 1 mole of \( N_{2} \) at \( 27 \mathrm{C} \) will be approximately
• The quantity \( \frac{2 U}{f k T} \) represents (where \( U= \) internal energy of gas
• A cyclic heat engine does \( 50 \mathrm{kJ} \) of work per cycle. If efficiency of engine is \( 75 \% \) the heat rejected per cycle will be:
• Thermistor material is pressed

⚔️ Practice NEET Physics free + battle 1v1 →