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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is (take γ = 5/3):

1. 64P
2. 32P
3. P/64
4. 16P

Correct answer: P/64

Solution

In the isothermal process, PV = constant, so the pressure after the first expansion is P/2. In the adiabatic process, PV^γ = constant. Using this, the final pressure is calculated as P_final = (P/2) * (2^5) = P/64.

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