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The Young's modulus of steel is twice that of brass. Two wires of same length and of same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of:

1. 2 : 1
2. 4 : 1
3. 1 : 1
4. 1 : 2

Correct answer: 1 : 2

Solution

The extension in a wire is inversely proportional to Young's modulus for the same length, area, and applied force. Since the Young's modulus of steel is twice that of brass, the force (weight) on the steel wire must be half that on the brass wire to achieve the same extension. Thus, the ratio is 1:2.

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