Correct answer: T = 2π√(l/(g+a))
The time period of a simple pendulum is given by T = 2π√(l/g_eff), where g_eff is the effective acceleration due to gravity. In this case, the rocket's upward acceleration adds to g, making g_eff = g + a. Substituting this into the formula gives T = 2π√(l/(g+a)).