Exams › NEET › Physics

A small object of uniform density rolls up a curved surface with an initial velocity ‘v’. It reaches upto a maximum height of \( \frac{3v^2}{4g} \) with respect to the initial position. The object is a

1. solid sphere
2. hollow sphere
3. disc
4. ring

Correct answer: solid sphere

Solution

The maximum height reached depends on the rotational kinetic energy and moment of inertia of the object. For a solid sphere, the moment of inertia is lowest among the given options, leading to the given height formula.

Related NEET Physics questions

• A uniform rod is resting freely over a smooth horizontal plane. A particle moving horizontally strikes at one end of the rod normally and gets stuck. Then This question has multiple correct options
• The dimensional formula of torque is
• The moment of the force, \( \mathbf{F} = 4\mathbf{i} + 5\mathbf{j} - 6\mathbf{k} \) at \((2, 0, -3)\), about the point \((2, -2, -2)\), is given by
• An object flying in air with velocity (20i + 25j − 12k) suddenly breaks into two pieces whose masses are in the ratio 1 : 5. The smaller mass flies off with a velocity (100i + 35j + 8k). The velocity of the larger piece will be
• At maximum compression, the solid cylinder will stop so loss in kinetic energy of the cylinder equals gain in potential energy of the spring. What is the expression for the energy?
• Two persons of masses 55 kg and 65 kg respectively, are at the opposite ends of a boat. The length of the boat is 3.0 m and weighs 100 kg. The 55 kg man walks up to the 65 kg man and sits with him. If the boat is in still water the centre of mass of the system shifts by:

⚔️ Practice NEET Physics free + battle 1v1 →