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Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is:

1. 2/3 M l²
2. 13/3 M l²
3. 1/3 M l²
4. 4/3 M l²

Correct answer: 13/3 M l²

Solution

The moment of inertia of each rod about the center of the square and perpendicular to its plane is calculated using the parallel axis theorem. Adding the contributions of all four rods gives the total moment of inertia as (13/3) M l².

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