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The moment of inertia of a disc of mass M and radius R about an axis, which is tangential to the circumference of the disc and parallel to its diameter, is
- 3/2 MR²
- 2/3 MR²
- 4/5 MR²
- 5/4 MR²
Correct answer: 3/2 MR²
Solution
The moment of inertia of a disc about its diameter is (1/4)MR², and using the parallel axis theorem, the moment of inertia about a tangential axis parallel to the diameter is I = (1/4)MR² + MR² = (3/2)MR².
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