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A thin rod of length L and mass M is bent at its midpoint into two halves so that the angle between them is 90°. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is:
- ML²/24
- ML²/12
- ML²/6
- √2 ML²/6
Correct answer: ML²/12
Solution
The rod is bent into two equal halves, each of length L/2. The moment of inertia of each half about the given axis is (1/3)ML²/4 (using the formula for a rod about one end). Adding the contributions of both halves gives ML²/12.
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