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The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc is
- 2/5 MR²
- 3/2 MR²
- 1/2 MR²
- MR²
Correct answer: 3/2 MR²
Solution
The moment of inertia of a uniform circular disc about its diameter is (1/4)MR². Using the parallel axis theorem, the moment of inertia about an axis touching the disc at its diameter and normal to the disc is (1/4)MR² + MR² = (3/2)MR².
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