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ExamsNEETPhysics

The angular speed of an engine wheel making 90 revolutions per minute is:

  1. 1.5π rad/s
  2. 3π rad/s
  3. 4.5π rad/s
  4. 6π rad/s

Correct answer: 1.5π rad/s

Solution

The angular speed is calculated as ω = 2π × (revolutions per second). Converting 90 revolutions per minute to revolutions per second gives 90/60 = 1.5 revolutions per second. Thus, ω = 2π × 1.5 = 3π rad/s.

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