The angular speed of an engine wheel making 90 revolutions per minute is:
1.5π rad/s
3π rad/s
4.5π rad/s
6π rad/s
Correct answer: 1.5π rad/s
Solution
The angular speed is calculated as ω = 2π × (revolutions per second). Converting 90 revolutions per minute to revolutions per second gives 90/60 = 1.5 revolutions per second. Thus, ω = 2π × 1.5 = 3π rad/s.