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A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed of 2.00 rad/sec. In a time of 2 sec it has rotated through an angle (in radian) of:

1. 10
2. 12
3. 4
4. 6

Correct answer: 12

Solution

The angular displacement is given by θ = ω₀t + (1/2)αt². Substituting ω₀ = 2 rad/s, α = 3 rad/s², and t = 2 s, we get θ = (2)(2) + (1/2)(3)(2²) = 4 + 6 = 12 rad.

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