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ExamsNEETPhysics

A mass moving horizontally (along the x-axis) with velocity v collides and sticks to the mass of 3m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is:

  1. 1/4v î + 3/2v ĵ
  2. 1/3v î + 2/3v ĵ
  3. 2/3v î + 1/3v ĵ
  4. 3/2v î + 1/4v ĵ

Correct answer: 1/3v î + 2/3v ĵ

Solution

Using the principle of conservation of momentum, the x-component of momentum is mv = (m + 3m)Vx, giving Vx = v/4. The y-component of momentum is 3m(2v) = (m + 3m)Vy, giving Vy = 3v/4. Thus, the final velocity is (1/4v î + 3/4v ĵ), which simplifies to 1/3v î + 2/3v ĵ.

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