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Given r = 20/π, v_j = 80 m/sec ⇒ ω_j = 80π/20 ⇒ 4π. θ = 2πeN = 4π radian. From equation, ω² = ω₀² + 2αθ. (4π)² = 0 + 2α.4π. α = 2π. Tangential acceleration a_t = α.r. a_t = 2π.20/π = 40 m/sec².

1. Tangential acceleration a_t = α.r.
2. a_t = 2π.20/π = 40 m/sec².
3. Linear velocity v = rω.
4. v₁/v₂ = r₁/r₂ = R/r.

Correct answer: a_t = 2π.20/π = 40 m/sec².

Solution

The calculation for tangential acceleration is correctly shown as a_t = α.r = 2π.20/π = 40 m/sec², which matches option B.

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