Calculate the kinetic energy of an electron when the photon energy is 2.48 eV and the work function is 1.9 eV.

K.E. = hν − hν₀ = hc/λ − hν₀ = 12375/5000 − 1.9 = 0.58 eV
K.E. = hν − hν₀ = hc/λ − hν₀ = 12375/5000 − 1.9 = 1.58 eV
K.E. = hν − hν₀ = hc/λ − hν₀ = 12375/5000 − 1.9 = 2.48 eV
K.E. = hν − hν₀ = hc/λ − hν₀ = 12375/5000 − 1.9 = 0.48 eV

Correct answer: K.E. = hν − hν₀ = hc/λ − hν₀ = 12375/5000 − 1.9 = 0.58 eV

Solution

The kinetic energy of the electron is calculated using the photoelectric equation: K.E. = Photon Energy - Work Function. Substituting the given values, K.E. = 2.48 eV - 1.9 eV = 0.58 eV. Thus, option A is correct.

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