In the Young’s double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wavelength of light used). The intensity at a point where the path difference is λ/4, will be:

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Accepted Answer

K/2. The intensity in Young's double-slit experiment is proportional to the square of the resultant amplitude. For a path difference of λ/4, the phase difference is π/2, and the resultant amplitude is reduced by a factor of √2. Thus, the intensity becomes K/2.

In the Young’s double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wavelength of light used). The intensity at a point where the path difference is λ/4, will be:

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