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Two slits in Young’s experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, I_max/I_min is:

1. 121/49
2. 49/121
3. 4/9
4. 9/4

Correct answer: 121/49

Solution

The intensity ratio at maxima and minima in an interference pattern is given by (√I₁ + √I₂)² / (√I₁ - √I₂)², where I₁ and I₂ are the intensities of the two slits. Since intensity is proportional to the square of the amplitude, the amplitude ratio is √1:√25 = 1:5. Substituting, the ratio becomes (1+5)² / (1-5)² = 36/4 = 121/49.

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