Exams › NEET › Physics

The current in self-inductance L = 40 mH is to be increased uniformly from 1 amp to 11 amp in 4 milliseconds. The e.m.f. induced in the inductor during the process is

1. 100 volt
2. 0.4 volt
3. 4.0 volt
4. 440 volt

Correct answer: 440 volt

Solution

The induced emf in an inductor is given by the formula E = L * (dI/dt). Here, L = 40 mH = 0.04 H, dI = 11 A - 1 A = 10 A, and dt = 4 ms = 0.004 s. Substituting, E = 0.04 * (10 / 0.004) = 0.04 * 2500 = 100 V. Thus, the correct answer is 100 V.

Related NEET Physics questions

• Which of the following statement regarding transformer is incorrect?
• Which one of the following statements is true?
• Which statement is incorrect related to induced electric field due to changing magnetic flux?
• A dynamo produces an electric current. It is based on the principle:
• In electromagnetic induction, the induced E.M.F is independent of
• A conductor is moved in a varying magnetic field. Name the law which determines the direction of current induced in the conductor:

⚔️ Practice NEET Physics free + battle 1v1 →