Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I = I₀ sin ωt, where I₀ = 10A and ω = 100π rad/sec. The maximum value of e.m.f. in the second coil is

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5π. The induced emf in the second coil is given by e = M * (dI/dt). Differentiating I = I₀ sin(ωt), we get dI/dt = I₀ω cos(ωt). The maximum emf occurs when cos(ωt) = 1, so e_max = M * I₀ * ω. Substituting M = 0.005 H, I₀ = 10 A, and ω = 100π rad/s, we get e_max = 0.005 * 10 * 100π = 5π V.

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I = I₀ sin ωt, where I₀ = 10A and ω = 100π rad/sec. The maximum value of e.m.f. in the second coil is

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