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A source and an observer move away from each other, with a velocity of 10 m/s with respect to ground. If the observer finds the frequency of sound coming from the source as 1950 Hz, then original frequency of source is (velocity of sound in air = 340 m/s)

1. 1950 Hz
2. 2068 Hz
3. 2132 Hz
4. 2486 Hz

Correct answer: 2068 Hz

Solution

The Doppler effect formula for sound when the source and observer move away is f' = f(v / (v + vs)), where f' is the observed frequency, f is the source frequency, v is the speed of sound, and vs is the relative velocity. Rearranging for f, we get f = f'(v + vs) / v. Substituting f' = 1950 Hz, v = 340 m/s, and vs = 10 m/s, we find f = 2068 Hz.

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