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The transverse wave represented by the equation y = 4 sin(π/6) sin(3x − 15t) has

1. amplitude = 4
2. wavelength = 4π/3
3. speed of propagation = 5
4. period = π/15

Correct answer: speed of propagation = 5

Solution

The wave equation is y = 4 sin(π/6) sin(3x − 15t). The speed of propagation is given by v = ω/k, where ω = 15 and k = 3. Thus, v = 15/3 = 5.

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