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Two waves are approaching each other with a velocity of 20 m/s and frequency n. The distance between two consecutive nodes is

1. 20/n
2. 10/n
3. 5/n
4. n/10

Correct answer: 10/n

Solution

The distance between two consecutive nodes in a standing wave is half the wavelength (λ/2). The wavelength is given by λ = v/n, where v is the velocity and n is the frequency. Thus, the distance between two nodes is (v/n)/2 = 10/n.

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