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We know that the time period (T) = 2π√(l/g). If g' = g_effective, since the negatively charged bob is attracted by the positively charged plate, therefore acceleration due to gravity will increase and time period will decrease.

1. 2π√(l/g')
2. 1/√8
3. 1/√2
4. 1/√3

Correct answer: 2π√(l/g')

Solution

The time period of a simple pendulum is given by T = 2π√(l/g). If the effective acceleration due to gravity increases to g', the time period will decrease and become T = 2π√(l/g'). Thus, the correct expression is option A.

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