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A transverse wave is represented by the equation y = y₀ sin [2π/λ (vt − x)]. For what value of λ is the maximum particle velocity equal to two times the wave velocity?
- λ = 2πy₀
- λ = πy₀/3
- λ = πy₀/2
- λ = πy₀
Correct answer: λ = πy₀/2
Solution
The maximum particle velocity is given by vmax = ωy₀, where ω = 2πv/λ. Setting vmax = 2v, we get 2πv/λ * y₀ = 2v. Simplifying, λ = πy₀/2.
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