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T = 2π√(l/g). If l is increased by 4 times, time period will increase by:

1. 2 times
2. 4 times
3. √2 times
4. √l times

Correct answer: 2 times

Solution

The time period of a simple pendulum is given by T = 2π√(l/g). If l is increased by 4 times, the new time period becomes T' = 2π√(4l/g) = 2π√4√(l/g) = 2T. Hence, the time period increases by 2 times.

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