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A particle is undergoing simple harmonic motion with an acceleration of 20 m/s² and displacement of 5 m. Find the time period of the motion.

1. π s
2. 2π s
3. π/2 s
4. 4π s

Correct answer: π s

Solution

In SHM, acceleration is given by a = -ω²x, where ω is the angular frequency and x is the displacement. Substituting a = 20 m/s² and x = 5 m, we get ω² = 20/5 = 4, so ω = 2 rad/s. The time period T = 2π/ω = 2π/2 = π s.

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