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The distance covered by a particle undergoing SHM in one time period is (amplitude = A).

1. 4A
2. Zero
3. A
4. 2A

Correct answer: 4A

Solution

In one time period, a particle in SHM moves from one extreme to the other, back to the first extreme, and then returns to its starting point. This covers a total distance of 4A (A + A + A + A).

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