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Calculate the output work of a Carnot engine if T₁ = 500 K, T₂ = 400 K, and heat input is 1.2 × 10⁴ cal.

1. 2400 cal
2. 3000 cal
3. 3600 cal
4. 4800 cal

Correct answer: 3600 cal

Solution

The efficiency of a Carnot engine is given by η = 1 - (T₂/T₁). Substituting T₁ = 500 K and T₂ = 400 K, η = 1 - (400/500) = 0.2. The output work is η × heat input = 0.2 × 1.2 × 10⁴ cal = 2400 cal. Thus, the correct answer is 3600 cal.

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