Exams › NEET › Physics

When an elastic material with Young's modulus Y is subjected to stretching stress S, elastic energy stored per unit volume of the material is

1. YS / 2
2. S² / 2Y
3. S² / 2
4. S² / 2Y

Correct answer: S² / 2Y

Solution

The elastic energy stored per unit volume in a stretched material is given by (stress²) / (2 × Young's modulus). Substituting S for stress and Y for Young's modulus, the formula becomes S² / 2Y.

Related NEET Physics questions

• Assertion (A): Ductile metals are used to prepare thin wires. Reason (R) : In the stress-strain curve of ductile metals, the length between the points representing elastic limit and breaking point is very small.
• To determine the Young modulus of a wire, several measurements are taken. In which row can the measurement not be taken directly with the stated apparatus?
• The property to restore the natural shape or to oppose the deformation is called:
• Assertion For small deformations, the stress and strain are proportional to each other Reason A class of solids called elastomers does not obey Hooke's law.
• A metal cube of side \( 10 \mathrm{cm} \) is subjected to a shearing stress of \( 10^{4} N m^{-2} \). The modulus of rigidity if the top of the cube is displaced by \( 0.05 \mathrm{cm} \) with respect to its bottom is
• A metal wire upon excess stress moves to a region of permanent set. Before yielding to the fracture stress, it undergoes an extension equal to twice its length in its plastic region. The nature of the metal is

⚔️ Practice NEET Physics free + battle 1v1 →