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Applying conservation law of angular momentum, I₀ω₀ = I₁ω₁ + I₂ω₂. The moment of inertia I₂ is given by:

1. I₂ = (M²) + 4(m)(r²)
2. I₂ = (M²) + 4(m)(r²) = (M + 4m)²
3. I₂ = (M²) + 4(m)(r²) = (M + 4m)
4. I₂ = (M²) + 4(m)(r²) = (M + 4m)³

Correct answer: I₂ = (M²) + 4(m)(r²)

Solution

The moment of inertia I₂ is given as the sum of the square of the mass M and four times the product of mass m and the square of radius r. This matches option A.

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