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A constant torque of 1000 N-m turns a wheel of moment of inertia 200 kg-m² about an axis through its centre. Its angular velocity after 3 seconds is

1. (a) 1 rad/s
2. (b) 5 rad/s
3. (c) 10 rad/s
4. (d) 15 rad/s

Correct answer: (c) 10 rad/s

Solution

The angular acceleration is given by α = τ/I, where τ is the torque and I is the moment of inertia. Substituting the values, α = 1000/200 = 5 rad/s². Using ω = αt, where t = 3 s, we get ω = 5 × 3 = 15 rad/s.

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