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A wheel having moment of inertia 2 kg-m² about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel’s rotation in one minute would be:

1. π / 18 N-m
2. 2π / 15 N-m
3. π / 12 N-m
4. π / 15 N-m

Correct answer: π / 15 N-m

Solution

The angular velocity is converted from 60 rpm to rad/s as ω = 2π × (60/60) = 2π rad/s. Using the equation τ = Iα, where α = (ω - 0)/t = 2π/60 rad/s², and I = 2 kg-m², we get τ = 2 × (2π/60) = π/15 N-m.

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