The distance between the ends of the wings of an airplane is $ 50 m $. It is flying in a horizontal plane at a speed of $ 360 K m / $hour. The vertical component of earth's magnetic field at that place is $ 2.0 \times 10^{-4} W b / m^{2}, $ then the potential difference induced betwe

Question

The distance between the ends of the wings of an airplane is $ 50 m $. It is flying in a horizontal plane at a speed of $ 360 K m / $hour. The vertical component of earth's magnetic field at that place is $ 2.0 \times 10^{-4} W b / m^{2}, $ then the potential difference induced between the ends of the wings will be

Accepted Answer

$ 1.0 v o l t $. The airplane wings act like a conductor moving perpendicular to the vertical magnetic field, so the induced emf is $\varepsilon = B\ell v$. Substituting $B=2.0\times10^{-4}\,\text{T}$, $\ell=50\,\text{m}$, and $v=360\,\text{km/h}=100\,\text{m/s}$ gives $\varepsilon=1.0\,\text{V}$.

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