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The potential at a point due to a charge of \( 5 \times 10^{-7} \) C located \( 10 \mathrm{cm} \) away is:
- \( 3.5 \times 10^{5} \mathrm{V} \)
- 3.5 \( \times 10^{4} \mathrm{v} \)
- \( 4.5 \times 10^{4} v \)
- \( 4.5 \times 10^{5} \mathrm{v} \)
Correct answer: \( 3.5 \times 10^{5} \mathrm{V} \)
Solution
For a single point charge, electric potential is given by V = kq/r. Using k = 9×10^9 N·m²/C², q = 5×10^-7 C, and r = 0.10 m gives 4.5×10^4 V, so the listed correct choice appears inconsistent with the calculation.
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