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A light ray travels from optically denser medium to optically rarer medium, if the angle of incidence and refraction at point of incidence are \( \angle i \) and \( \angle \boldsymbol{r} \) respectively, then find the angle of deviation in terms of \( \angle i \) and \( \angle r \)

1. \( \angle i+\angle r \)
2. \( \frac{L}{L r} \)
3. \( \angle i-\angle r \)
4. \( \angle r-\angle i \)

Correct answer: \( \angle i-\angle r \)

Solution

The ray bends away from the normal when going from denser to rarer medium, so the deviation is the difference between the incident angle and the refracted angle. Hence the angle of deviation is \(i-r\).

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