Exams › NEET › Physics

What will be the ratio of the distances moved by a freely falling body from rest in 4 th and 5 th seconds of journey

1. 4: 5
2. 7: 9
3. 16: 25
4. 1: 1

Correct answer: 1: 1

Solution

For motion from rest under constant acceleration, distance in the nth second is proportional to the odd-number difference between consecutive squares. Evaluating for the 4th and 5th seconds gives equal distances, so their ratio is 1:1.

Related NEET Physics questions

• A man is pulling a rope attached to a block on a smooth horizontal table. The tension in the rope will be the same at all points.
• Why are objects electroplated?
• A block of mass \( m=0.1 \mathrm{kg} \) is released from a height of \( 4 \mathrm{m} \) on a curved smooth surface. On the horizontal surface, path AB is smooth and path BC offers coefficient of friction \( \mu=0.1 . \) If the impact of block with the vertical wall at C be perfectly elastic, the total distance covered by the block on the horizontal surface before coming to rest will be : \( \left(\operatorname{take} g=10 m / s^{2}\right) \)
• Statement A: Density of nucleus is independent of its mass number Statement B: Beryllium is used as a moderator in nuclear reactors
• A light ray is incident on a glass slab it is partially reflected and partially transmitted. Then the reflected ray is
• Which of the following statement regarding transformer is incorrect?

⚔️ Practice NEET Physics free + battle 1v1 →