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If two metallic plates of equal thicknesses and thermal conductivities 1 K and 2 K are put together face to face and a common plate is constructed, then the equivalent thermal conductivity of this plate will be
- 2 1 2 1 K K K K
- 2 1 2 1 2 K K K K
- 2 1 2 / 3 2 2 2 1 ) ( K K K K
- 2 1 2 / 3 2 2 2 1 2 ) ( K K K K
Correct answer: 2 1 2 1 2 K K K K
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