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The binding energy of deuteron H 2 1 is 1.112 MeV per nucleon and an   particle He 4 2 has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction Q He H H    4 2 2 1 2 1 , the energy Q released is

1. 1 MeV
2. 11.9 MeV
3. 23.8 MeV
4. 931 MeV

Correct answer: 23.8 MeV

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